x^2+35x-4250=0

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Solution for x^2+35x-4250=0 equation:



x^2+35x-4250=0
a = 1; b = 35; c = -4250;
Δ = b2-4ac
Δ = 352-4·1·(-4250)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18225}=135$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-135}{2*1}=\frac{-170}{2} =-85 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+135}{2*1}=\frac{100}{2} =50 $

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